individual probability वाक्य
उदाहरण वाक्य
मोबाइल
- For this kind of judgment, anchoring on the individual probabilities results in an overestimation of the combined probability.
- Another caveat is that individual probability judgments are often biased toward extreme values ( e . g ., 0 or 1 ).
- In the second stage, the researcher corrects for self-selection by incorporating a transformation of these predicted individual probabilities as an additional explanatory variable.
- Formalising this insight required transformations to be applied to the cumulative probability distribution function, rather than to individual probabilities ( Quiggin, 1982, 1993 ).
- As these individual probabilities are closely guarded secrets, it is possible that the advertised machines with high return to player simply increase the probabilities of these jackpots.
- You can find each of the individual probabilities, but you can't use them to get an overall probability since the total number of rolls is not defined.
- Note that for a discrete distribution, computing the CDF is not in general too difficult : we simply add up the individual probabilities for the various points of the distribution.
- :: Yeah, with any two random unrelated factors, the probability of having both is the individual probabilities multiplied together .-- List of good deeds 20 : 05, 25 May 2012 ( UTC)
- For any specific value x, the chance that I'll choose x is 0, but the chance of me choosing any number between 0 and 1 should be the sum of these individual probabilities, but is equal to 1.
- Therefore, the correct ( quantum-mechanical ) formula for the probability for an electron to move from a point A to a point B includes the classical part ( individual probabilities of diffusive paths ) and a number of interference terms ( products of the amplitudes corresponding to different paths ).
- How would I go about determining the probability that an element is part of " Collection B " if it has the three most significant features, in this case Feature 1, Feature 2, and an absence of Feature 5 ( with individual probabilities of 0.96?.03, 0.88?.04, and 0.66?.08 respectively )?
- How would I go about determining the probability that an element is part of " Collection B " if it has the three most significant features, in this case Feature 1, Feature 2, and an " absence " of Feature 5 ( with individual probabilities of 0.96?.03, 0.88?.04, and 0.66?.08 respectively )?
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